9.2.1 Filtered Cocompleteness
Recall that an $\infty $-category $\operatorname{\mathcal{C}}$ is cocomplete if every small diagram in $\operatorname{\mathcal{C}}$ admits a colimit (Definition 7.6.6.1). It will sometimes be helpful to break this down into two separate conditions:
Proposition 9.2.1.1. An $\infty $-category $\operatorname{\mathcal{C}}$ is cocomplete if and only if it satisfies both of the following conditions:
- $(a)$
The $\infty $-category $\operatorname{\mathcal{C}}$ is finitely cocomplete: that is, it admits finite colimits.
- $(b)$
The $\infty $-category $\operatorname{\mathcal{C}}$ admits small filtered colimits.
Proof.
Assume that conditions $(a)$ and $(b)$ are satisfied; we will show that $\operatorname{\mathcal{C}}$ is cocomplete (the converse is immediate from the definitions). Let $K$ be a small simplicial set; we wish to show that $\operatorname{\mathcal{C}}$ admits $K$-indexed colimits. Let $\{ K_{\alpha } \} _{\alpha \in A}$ be the collection of all finite simplicial subsets of $K$. For $\alpha ,\beta \in A$, let us write $\alpha \leq \beta $ if $K_{\alpha }$ is contained in $K_{\beta }$. Then $(A, \leq )$ is a small directed partially ordered set, so $\operatorname{\mathcal{C}}$ admits $\operatorname{N}_{\bullet }(A)$-indexed colimits by virtue of condition $(b)$. It follows from condition $(a)$ that $\operatorname{\mathcal{C}}$ also admits $K_{\alpha }$-indexed colimits, for each $\alpha \in A$. Applying Corollary 9.1.6.6, we conclude that $\operatorname{\mathcal{C}}$ admits colimits indexed by $K = \varinjlim _{\alpha \in A} K_{\alpha }$, as desired.
$\square$
Proposition 9.2.1.1 has a counterpart for $\kappa $-cocomplete $\infty $-categories, where $\kappa $ is any regular cardinal. Before formulating it, it will be convenient to introduce some terminology.
Definition 9.2.1.3. Let $\kappa \leq \lambda $ be regular cardinals. We will say that an $\infty $-category $\operatorname{\mathcal{C}}$ is $(\kappa ,\lambda )$-cocomplete if it admits $\operatorname{\mathcal{K}}$-indexed colimits for every $\infty $-category $\operatorname{\mathcal{K}}$ which is $\lambda $-small and $\kappa $-filtered.
Warning 9.2.1.4. Definition 9.2.1.3 makes sense for every pair of regular cardinals $\kappa \leq \lambda $. However, it is well behaved under the additional assumption $\kappa \trianglelefteq \lambda $ (see Definition 9.1.7.5). Roughly speaking, this condition guarantees that there are “enough” examples of $\lambda $-small $\kappa $-filtered $\infty $-categories.
Example 9.2.1.6. Let $X$ be a Kan complex. Then $X$ is $(\kappa ,\lambda )$-cocomplete when viewed as an $\infty $-category, for every pair of regular cardinals $\kappa \leq \lambda $. This follows from Corollary 7.2.3.5, since every filtered $\infty $-category is weakly contractible (Proposition 9.1.1.18).
Proposition 9.2.1.7. Let $\kappa $ and $\lambda $ be regular cardinals satisfying $\kappa \trianglelefteq \lambda $. For every $\infty $-category $\operatorname{\mathcal{C}}$, the following conditions are equivalent:
- $(1)$
The $\infty $-category $\operatorname{\mathcal{C}}$ is $\lambda $-cocomplete.
- $(2)$
The $\infty $-category $\operatorname{\mathcal{C}}$ is both $\kappa $-cocomplete and $(\kappa ,\lambda )$-cocomplete.
Proof of Proposition 9.2.1.7.
The implication $(1) \Rightarrow (2)$ is trivial (and does not require the assumption $\kappa \trianglelefteq \lambda $). To prove the converse, we proceed as in the proof of Proposition 9.2.1.1. Assume that $\operatorname{\mathcal{C}}$ is both $\kappa $-cocomplete and $(\kappa ,\lambda )$-cocomplete; we wish to show that every $\lambda $-small diagram $K \rightarrow \operatorname{\mathcal{C}}$ admits a colimit. Using Lemma 9.1.7.18, we can realize $K$ as the colimit of a diagram of $\kappa $-small simplicial subsets $\{ K_{\alpha } \} _{\alpha \in A}$ indexed by a $\lambda $-small $\kappa $-directed partially ordered set $(A, \leq )$. Since $\operatorname{\mathcal{C}}$ is $\kappa $-cocomplete, it admits $K_{\alpha }$-indexed colimits for each $\alpha \in A$. Our assumption that $\operatorname{\mathcal{C}}$ is $(\kappa ,\lambda )$-cocomplete guarantees that it also admits $\operatorname{N}_{\bullet }(A)$-indexed colimits. Applying Corollary 9.1.6.6, we conclude that $\operatorname{\mathcal{C}}$ admits colimits indexed by $K = \varinjlim _{\alpha \in A} K_{\alpha }$, as desired.
$\square$
Corollary 9.2.1.9. Let $\kappa $ be a small regular cardinal. Then an $\infty $-category $\operatorname{\mathcal{C}}$ is cocomplete if and only if it is $\kappa $-cocomplete and admits small $\kappa $-filtered colimits.
Proof.
Apply Proposition 9.2.1.7 in the special case where $\lambda = \operatorname{\Omega }$ is a strongly inaccessible cardinal (see Example 9.1.7.11).
$\square$
Corollary 9.2.1.10. Let $\lambda $ be a regular cardinal. Then an $\infty $-category $\operatorname{\mathcal{C}}$ is $\lambda $-cocomplete if and only if it is finitely cocomplete and admits $\lambda $-small filtered colimits.
Proof.
Apply Proposition 9.2.1.7 in the special case where $\kappa = \aleph _0$ (see Example 9.1.7.10).
$\square$
Definition 9.2.1.3 can often be simplified.
Proposition 9.2.1.11. Let $\kappa $ and $\lambda $ be regular cardinals satisfying $\kappa \triangleleft \lambda $. For every $\infty $-category $\operatorname{\mathcal{C}}$, the following conditions are equivalent:
- $(1)$
The $\infty $-category $\operatorname{\mathcal{C}}$ is $(\kappa ,\lambda )$-cocomplete.
- $(2)$
The $\infty $-category $\operatorname{\mathcal{C}}$ admits $\operatorname{N}_{\bullet }(A)$-indexed colimits, for every $\lambda $-small $\kappa $-directed partially ordered set $(A, \leq )$.
Proof.
The implication $(1) \Rightarrow (2)$ follows from Example 9.1.1.8, and the reverse implication follows by combining Theorem 9.1.8.7 with Corollary 7.2.2.12.
$\square$
Corollary 9.2.1.12. Let $\kappa $ be a small regular cardinal. Then an $\infty $-category $\operatorname{\mathcal{C}}$ admits small $\kappa $-filtered colimits if and only if it admits $\operatorname{N}_{\bullet }(A)$-indexed colimits, for every small $\kappa $-directed partially ordered set $(A, \leq )$.
Proof.
Apply Proposition 9.2.1.11 in the special case where $\lambda = \operatorname{\Omega }$ is a strongly inaccessible cardinal (see Example 9.1.7.11).
$\square$
Corollary 9.2.1.13. Let $\lambda $ be an uncountable regular cardinal. Then $\infty $-category $\operatorname{\mathcal{C}}$ admits $\lambda $-small filtered colimits if and only if it admits $\operatorname{N}_{\bullet }(A)$-indexed colimits, for every $\lambda $-small directed partially ordered set $(A, \leq )$.
Proof.
Apply Proposition 9.2.1.11 in the special case $\kappa = \aleph _0$ (see Example 9.1.7.10).
$\square$
Beware that Proposition 9.2.1.11 is not quite correct in the degenerate case $\kappa = \lambda $. Instead we have the following:
Proposition 9.2.1.14. Let $\kappa $ be a regular cardinal. Then:
If $\kappa $ is uncountable, then an $\infty $-category $\operatorname{\mathcal{C}}$ is $(\kappa ,\kappa )$-cocomplete if and only if it is idempotent-complete.
If $\kappa = \aleph _0$, then every $\infty $-category is $(\kappa ,\kappa )$-cocomplete.
Proof.
We will assume that $\kappa $ is uncountable (the case $\kappa = \aleph _0$ follows from Corollary 9.1.8.12). In this case, the $\infty $-category $\operatorname{N}_{\bullet }(\operatorname{Idem})$ of Construction 8.5.2.7 is both $\kappa $-small and $\kappa $-filtered (Example 9.1.1.10), so every $(\kappa ,\kappa )$-cocomplete $\infty $-category is idempotent-complete (Proposition 8.5.4.10). Conversely, suppose that $\operatorname{\mathcal{C}}$ is idempotent-complete; we wish to show that $\operatorname{\mathcal{C}}$ admits $\operatorname{\mathcal{K}}$-indexed colimits for every $\infty $-category $\operatorname{\mathcal{K}}$ which is both $\kappa $-small and $\kappa $-filtered. Proposition 9.1.8.11 guarantees the existence of a right cofinal functor $\operatorname{N}_{\bullet }(\operatorname{Idem}) \rightarrow \operatorname{\mathcal{K}}$, so the desired result is follows from Corollary 7.2.2.12.
$\square$
Proposition 9.2.1.15 (Transitivity). Let $\kappa $, $\lambda $, and $\mu $ be regular cardinals satisfying $\kappa \trianglelefteq \lambda \trianglelefteq \mu $. Then an $\infty $-category $\operatorname{\mathcal{C}}$ is $(\kappa ,\mu )$-cocomplete if and only if it is both $(\kappa ,\lambda )$-cocomplete and $(\lambda ,\mu )$-cocomplete.
Proof.
We will assume $\kappa < \lambda $ (otherwise, there is nothing to prove). Assume that $\operatorname{\mathcal{C}}$ is $(\kappa ,\lambda )$-cocomplete and $(\lambda ,\mu )$-cocomplete; we wish to show that it is $(\kappa ,\mu )$-cocomplete (the converse follows immediately from Remark 9.2.1.5, and requires only the assumption $\kappa \leq \lambda \leq \mu $). This follows from Corollary 9.1.6.6, since every $\mu $-small $\kappa $-filtered $\infty $-category $\operatorname{\mathcal{K}}$ can be realized as a $\mu $-small, $\lambda $-filtered colimit of $\lambda $-small $\kappa $-filtered $\infty $-categories (Corollary 9.1.7.16).
$\square$
Corollary 9.2.1.16. Let $\kappa $ and $\lambda $ be small regular cardinals satisfying $\kappa \trianglelefteq \lambda $. Then an $\infty $-category $\operatorname{\mathcal{C}}$ admits small $\kappa $-filtered colimits if and only if it admits small $\lambda $-filtered colimits and is $(\kappa ,\lambda )$-cocomplete.
Proof.
Apply Proposition 9.2.2.29 in the special case where $\lambda = \operatorname{\Omega }$ is a fixed strongly inaccessible cardinal (see Example 9.1.7.11).
$\square$
Corollary 9.2.1.17. Let $\lambda $ be a small regular cardinal. Then an $\infty $-category $\operatorname{\mathcal{C}}$ admits small filtered colimits if and only if it admits small $\lambda $-filtered colimits and $\lambda $-small filtered colimits.
Proof.
Apply Corollary 9.2.1.16 in the special case $\kappa = \aleph _0$ (see Example 9.1.7.10).
$\square$