# Kerodon

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### 2.2.7 Strictly Unitary $2$-Categories

We now introduce a special class of $2$-categories.

Definition 2.2.7.1. Let $\operatorname{\mathcal{C}}$ be a $2$-category. We will say that $\operatorname{\mathcal{C}}$ is strictly unitary if, for each $1$-morphism $f: X \rightarrow Y$ in $\operatorname{\mathcal{C}}$, the left and right unit constraints

$\lambda _{f}: \operatorname{id}_{Y} \circ f \xRightarrow {\sim } f \quad \quad \rho _{f}: f \circ \operatorname{id}_{X} \xRightarrow {\sim } f$

are identity $2$-morphisms of $\operatorname{\mathcal{C}}$.

Proposition 2.2.7.2. Let $\operatorname{\mathcal{C}}$ be a $2$-category. Then $\operatorname{\mathcal{C}}$ is strictly unitary if and only if the following conditions are satisfied:

$(a)$

For each $1$-morphism $f: X \rightarrow Y$ in $\operatorname{\mathcal{C}}$, we have $\operatorname{id}_{Y} \circ f = f = f \circ \operatorname{id}_{X}$.

$(b)$

For each object $X$ of $\operatorname{\mathcal{C}}$, the unit constraint $\upsilon _{X}: \operatorname{id}_{X} \circ \operatorname{id}_{X} \xRightarrow {\sim } \operatorname{id}_ X$ is the identity morphism from $\operatorname{id}_{X} \circ \operatorname{id}_{X} = \operatorname{id}_{X}$ to itself.

$(c)$

For every $1$-morphism $f: X \rightarrow Y$ in $\operatorname{\mathcal{C}}$, the associativity constraints $\alpha _{ \operatorname{id}_{Y}, \operatorname{id}_{Y}, f}$ and $\alpha _{ f, \operatorname{id}_ X, \operatorname{id}_ X}$ are equal to the identity (as $2$-morphisms from $f$ to itself).

Proof. If $\operatorname{\mathcal{C}}$ is strictly unitary, then $(a)$ is clear and $(b)$ follows from Corollary 2.2.1.15. Assume that $(a)$ and $(b)$ are satisfied. For any $1$-morphism $f: X \rightarrow Y$ in $\operatorname{\mathcal{C}}$, the left unit constraint $\lambda _{f}$ is characterized by the commutativity of the diagram

$\xymatrix@R =50pt@C=50pt{ \operatorname{id}_{Y} \circ ( \operatorname{id}_ Y \circ f) \ar@ {=>}[rr]^{ \alpha _{ \operatorname{id}_ Y, \operatorname{id}_ Y, f} } \ar@ {=>}[dr]_{ \operatorname{id}_{\operatorname{id}_ Y} \circ \lambda _ f} & & (\operatorname{id}_ Y \circ \operatorname{id}_ Y) \circ f \ar@ {=>}[dl]^{ \upsilon _ Y \circ \operatorname{id}_ f} \\ & \operatorname{id}_ Y \circ f, & }$

and is therefore the identity $2$-morphism if and only if $\alpha _{\operatorname{id}_ Y, \operatorname{id}_ Y, f}$ is an identity $2$-morphism (from $f$ to itself). Similarly, the right unit constraint $\rho _{f}$ is an identity $2$-morphism if and only if $\alpha _{ f, \operatorname{id}_ X, \operatorname{id}_ X }$ is an identity $2$-morphism in $\operatorname{\mathcal{C}}$. $\square$

Remark 2.2.7.3. Let $\operatorname{\mathcal{C}}$ be a strictly unitary $2$-category. Then $\operatorname{\mathcal{C}}$ satisfies the following stronger versions of conditions $(a)$ and $(c)$ of Proposition 2.2.7.2:

$(a')$

For every pair of objects $X,Y \in \operatorname{\mathcal{C}}$, the functors

$\underline{\operatorname{Hom}}_{\operatorname{\mathcal{C}}}(X,Y) \rightarrow \underline{\operatorname{Hom}}_{\operatorname{\mathcal{C}}}(X,Y) \quad \quad f \mapsto \operatorname{id}_{Y} \circ f$
$\underline{\operatorname{Hom}}_{\operatorname{\mathcal{C}}}(X,Y) \rightarrow \underline{\operatorname{Hom}}_{\operatorname{\mathcal{C}}}(X,Y) \quad \quad f \mapsto f \circ \operatorname{id}_ X$

are equal to the identity.

$(c')$

For every pair of $1$-morphisms $X \xrightarrow {f} Y \xrightarrow {g} Z$ in $\operatorname{\mathcal{C}}$, the associativity constraints $\alpha _{g, f, \operatorname{id}_ X}$, $\alpha _{ g, \operatorname{id}_ Y, f}$, and $\alpha _{\operatorname{id}_ Z, g, f}$ are equal to the identity (as $2$-morphisms from $g \circ f$ to itself).

Here $(a')$ follows from the naturality of the left and right unit constraints (Remark 2.2.1.13), and $(c')$ follows from Propositions 2.2.1.14 and 2.2.1.16.

Example 2.2.7.4. Let $G$ be a group with identity element $1 \in G$, let $\Gamma$ be an abelian group on which $G$ acts by automorphisms, let $\alpha : G \times G \times G \rightarrow \Gamma$ be a $3$-cocycle, let $\operatorname{\mathcal{C}}$ be the monoidal category of Example 2.1.3.3, and let $B\operatorname{\mathcal{C}}$ be the $2$-category obtained by delooping $\operatorname{\mathcal{C}}$ (Example 2.2.2.5). The following conditions are equivalent:

• The $3$-cocycle $\alpha$ is normalized: that is, it satisfies the equations

$\alpha _{x,y,1} = \alpha _{x,1,y} = \alpha _{1,x,y} = 0$

for every pair of elements $x,y \in G$.

• The $2$-category $B\operatorname{\mathcal{C}}$ is strictly unitary, in the sense of Definition 2.2.7.1.

Remark 2.2.7.5. Let $\operatorname{\mathcal{C}}$ and $\operatorname{\mathcal{D}}$ be strictly unitary $2$-categories (Definition 2.2.7.1). Then a strictly unitary lax functor $F: \operatorname{\mathcal{C}}\rightarrow \operatorname{\mathcal{D}}$ is given by the following data:

• For each object $X \in \operatorname{\mathcal{C}}$, an object $F(X) \in \operatorname{\mathcal{D}}$.

• For every pair of objects $X,Y \in \operatorname{\mathcal{C}}$, a functor of ordinary categories

$F_{X,Y}: \underline{\operatorname{Hom}}_{\operatorname{\mathcal{C}}}(X,Y) \rightarrow \underline{\operatorname{Hom}}_{\operatorname{\mathcal{D}}}( F(X), F(Y) ).$
• For every pair of composable $1$-morphisms $X \xrightarrow {f} Y \xrightarrow {g} Z$ in $\operatorname{\mathcal{C}}$, a composition constraint $\mu _{g,f}: F(g) \circ F(f) \Rightarrow F(g \circ f)$, depending functorially on $f$ and $g$.

This data must be required to satisfy axiom $(c)$ of Definition 2.2.4.5, together with the identities $F( \operatorname{id}_ X) = \operatorname{id}_{F(X)}$ for each object $X \in \operatorname{\mathcal{C}}$ and $\mu _{\operatorname{id}_ Y, f} = \operatorname{id}_{ F(f)} = \mu _{f, \operatorname{id}_ X}$ for each $1$-morphism $f: X \rightarrow Y$ of $\operatorname{\mathcal{C}}$.

Remark 2.2.7.6. Let $\operatorname{\mathcal{C}}$ be a strictly unitary $2$-category, let $\{ \mu _{g,f} \}$ be a twisting cochain for $\operatorname{\mathcal{C}}$ (see Notation 2.2.6.7), and let $\operatorname{\mathcal{C}}'$ denote the twist of $\operatorname{\mathcal{C}}'$ with respect to $\{ \mu _{g,f} \}$ (Construction 2.2.6.8). The following conditions are equivalent:

$(1)$

The $2$-category $\operatorname{\mathcal{C}}'$ is strictly unitary.

$(2)$

For every $1$-morphism $f: X \rightarrow Y$ in $\operatorname{\mathcal{C}}$, both $\mu _{f, \operatorname{id}_ X}$ and $\mu _{\operatorname{id}_{Y},f}$ are identity $2$-morphisms (from $f \circ \operatorname{id}_{X} = f = \operatorname{id}_{Y} \circ f$ to itself).

If these conditions are satisfied, we will say that the twisting cochain $\{ \mu _{g,f} \}$ is normalized.

It is generally harmless to assume that a $2$-category $\operatorname{\mathcal{C}}$ is strictly unitary, by virtue of the following:

Proposition 2.2.7.7. Let $\operatorname{\mathcal{C}}$ be a $2$-category. Then there exists a strictly unitary isomorphism $\operatorname{\mathcal{C}}\simeq \operatorname{\mathcal{C}}'$, where $\operatorname{\mathcal{C}}'$ is a strictly unitary $2$-category.

Proof. Let $\mu = \{ \mu _{g,f} \}$ be the twisting cochain on $\operatorname{\mathcal{C}}$ given on composable $1$-morphisms $X \xrightarrow {f} Y \xrightarrow {g} Z$ by the formula

$\mu _{g,f} = \begin{cases} \lambda ^{-1}_{f}: f \Rightarrow g \circ f & \text{ if } g = \operatorname{id}_{Y} \\ \rho ^{-1}_{g}: g \Rightarrow g \circ f & \text{ if } f = \operatorname{id}_ Y \\ \operatorname{id}_{g \circ f}: g \circ f \Rightarrow g \circ f & \text{ otherwise. } \end{cases}$

Note that this prescription is consistent, since $\lambda _{f} = \upsilon _{Y} = \rho _{g}$ in the special case where $f = \operatorname{id}_ Y = g$ (Corollary 2.2.1.15). Let $\operatorname{\mathcal{C}}'$ be the twist of $\operatorname{\mathcal{C}}$ with respect to the cocycle $\{ \mu _{g,f} \}$ (Construction 2.2.6.8). Then $\operatorname{\mathcal{C}}'$ is a strictly unitary $2$-category (in the sense of Definition 2.2.7.1), and Exercise 2.2.6.9 supplies a strictly unitary isomorphism of $2$-categories $\operatorname{\mathcal{C}}\simeq \operatorname{\mathcal{C}}'$ $\square$

Remark 2.2.7.8. Let $\operatorname{2Cat}'_{\operatorname{ULax}}$ denote the subcategory of $\operatorname{2Cat}_{\operatorname{Lax}}$ (and full subcategory of $\operatorname{2Cat}_{\operatorname{ULax}}$) whose objects are strictly unitary $2$-categories and whose morphisms are strictly unitary lax functors. It follows from Proposition 2.2.7.7 that the inclusion $\operatorname{2Cat}'_{\operatorname{ULax}} \hookrightarrow \operatorname{2Cat}_{\operatorname{ULax}}$ is an equivalence of categories.

Remark 2.2.7.9. Let $G$ be a group and let $\Gamma$ be an abelian group with an action of $G$. When applied to the $2$-categories described in Example 2.2.7.4, Proposition 2.2.7.7 reduces to the assertion that every $3$-cocycle $\alpha : G \times G \times G \rightarrow \Gamma$ is cohomologous to a normalized $3$-cocycle $\alpha ': G \times G \times G \rightarrow \Gamma$.