Corollary 1.4.3.7. Let $\operatorname{\mathcal{C}}$ be an $\infty $-category, and let $f,g: X \rightarrow Y$ be morphisms of $\operatorname{\mathcal{C}}$ having the same source and target. Then $f$ and $g$ are homotopic (in the sense of Definition 1.4.3.1) if and only if there exists a map of simplicial sets $H: \Delta ^1 \times \Delta ^1 \rightarrow \operatorname{\mathcal{C}}$ satisfying $H|_{ \{ 0\} \times \Delta ^1} = f$, $H|_{ \{ 1\} \times \Delta ^1} = g$, $H|_{ \Delta ^1 \times \{ 0\} } = \operatorname{id}_ X$, and $H|_{ \Delta ^1 \times \{ 1\} } = \operatorname{id}_{Y}$, as indicated in the diagram
Proof. The “only if” direction is clear: if $\sigma $ is a homotopy from $f$ to $g$ (in the sense of Definition 1.4.3.1), then we can extend $\sigma $ to a map $H: \Delta ^1 \times \Delta ^1 \rightarrow \operatorname{\mathcal{C}}$ by taking $\tau $ to be the degenerate simplex $s^{1}_0( g )$. Conversely, suppose that there exists a map $\Delta ^1 \times \Delta ^1 \rightarrow \operatorname{\mathcal{C}}$, as indicated in the diagram
Then the $2$-simplex $\sigma $ is a homotopy from $f$ to $h$, and the $2$-simplex $\tau $ guarantees that $g$ is homotopic to $h$ (by virtue of Proposition 1.4.3.6). Since homotopy is an equivalence relation (Proposition 1.4.3.5), it follows that $f$ is homotopic to $g$. $\square$