$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$

Comments on Theorem

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Comment #1502 by Ken on

In the second step of the proof, why can we replace with ? There doesn't seem to exist an obvious map .

Comment #1509 by Kerodon on

Oops! Yes, that argument needs to be modified. Thanks!

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  • 2 comment(s) on Subsection 3.4.4: Mather's First Cube Theorem

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