# Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$

Go back to the page of Subsection 5.6.2.

Comment #1270 by Carles Sáez on

In the paragraph just after Definition 5.6.2.1, there are two $\operatorname{N}_{\bullet }^{\operatorname{hc}}(\operatorname{\mathcal{C}})$ that should be $\operatorname{N}_{\bullet }^{\operatorname{hc}}( \operatorname{Set_{\Delta }})$.

Comment #1275 by Kerodon on

Yep. Thanks!

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