Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$
$\Newextarrow{\xhookrightarrow}{10,10}{0x21AA}$

Comments on Lemma 11.9.3.7

Go back to the page of Lemma 11.9.3.7.

Comment #1395 by Daniel Gratzer on

There appears to be a LaTeX error in the final portion of this proof around.

Comment #1417 by Kerodon on

I think it must be a gerby issue. The output looks ok in the pdf.

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