Remark 4.8.8.8 (Uniqueness). Let $F: \operatorname{\mathcal{C}}\rightarrow \operatorname{\mathcal{D}}$ be a functor of $\infty $-categories. Then, for every integer $n$, the factorization of Theorem 4.8.8.3 is well-defined up to equivalence. More precisely, if the functor $F$ admits two factorizations
where the functors $F'_0$ and $F'_1$ are essentially $n$-categorical, and the functors $G_0$ are $G_1$ are categorically $(n+1)$-connective, then we can find a commutative diagram
where the vertical maps are equivalences of $\infty $-categories. To prove this, we can use Corollary 4.5.2.23 to reduce to the case where $F'_0$ is a monomorphism of simplicial sets and $G_1$ is an isofibration. In this case, Corollary 4.8.7.18 (and Remark 4.8.7.19) guarantee that the functors $F'_0$ and $G_1$ induce a trivial Kan fibration
In particular, this map is surjective on vertices, so the lifting problem
has a solution. A choice of solution determines a commutative diagram
It follows from Proposition 4.8.7.12 that the functor $H$ is categorically $(n+1)$-connective, and from Remark 4.8.6.7 that $H$ is essentially $n$-categorical. Applying Remark 4.8.5.11, we conclude that $H$ is an equivalence of $\infty $-categories.