Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$
$\Newextarrow{\xhookrightarrow}{10,10}{0x21AA}$

Comments on Theorem 8.1.8.4

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Comment #883 by Elizabeth Goldfinch on

In the second paragraph of the proof, "is factors as" should read "factors as".

Comment #885 by Kerodon on

Yep. Thanks!

Comment #1062 by Elizabeth Goldfinch on

In condition (2) in the proof, "with both with" should just be "with". In condition (3), "element of" should be "as elements of". In the second display in the proof, should be .

Comment #1063 by Elizabeth Goldfinch on

In the big commutative diagram, there are a couple of errors: in the arrow pointing from to , the subscript for should be not , and in the arrow pointing from to , should be .

Comment #1065 by Elizabeth Goldfinch on

Oops, in my comment #1062, the last expression was meant to be .

Comment #1066 by Elizabeth Goldfinch on

Four instances of a subscript 01 in the proof should be changed to 10: in the first display in the proof, in the big commutative diagram in the arrow from to , and in the antepenultimate and final displays.

Comment #1080 by Kerodon on

Yep. Thanks!

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  • 1 comment(s) on Section 8.1: Twisted Arrows and Cospans

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