Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$
$\Newextarrow{\xhookrightarrow}{10,10}{0x21AA}$

Comments on Lemma 6.3.7.15

Go back to the page of Lemma 6.3.7.15.

Comment #1754 by Claudius on

The statement misses the assumption that every be nonsingular.

Comment #1765 by Kerodon on

Yep. Thanks!

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