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$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$
$\Newextarrow{\xhookrightarrow}{10,10}{0x21AA}$

Comments on Proposition 6.3.5.4

Go back to the page of Proposition 6.3.5.4.

Comment #1746 by Claudius on

In the proof, the in the definition of and should probably be .

Comment #1747 by Claudius on

In the proof, the isomorphisms of functor spaces in the displayed formula are identical.

Comment #1751 by Kerodon on

Yep. Thanks!

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  • 2 comment(s) on Subsection 6.3.5: Fiberwise Localization

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