Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$
$\Newextarrow{\xhookrightarrow}{10,10}{0x21AA}$

Comments on Proposition 11.6.0.49

Go back to the page of Proposition 11.6.0.49.

Comment #1759 by Claudius on

In the first sentence of the proof, should probably be in (not just a morphism in ).

Comment #1770 by Kerodon on

Yep. Thanks!

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