# Kerodon

$\Newextarrow{\xRightarrow}{5,5}{0x21D2}$ $\newcommand\empty{}$

Go back to the page of Proposition 5.1.4.13.

Comment #888 by Carles Sáez on

In the last paragraph of the proof, from "Then $g$ is $q'$-cartesian" up to "$f$ is also $q$-cartesian" I think all $q$'s should be $p$'s.

Also, at the condition $(*)$ there's a superflous "is an edge".

Comment #891 by Kerodon on

Yep. Thanks!

There are also:

• 5 comment(s) on Section 5.1: Cartesian Fibrations

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