Corollary 9.2.7.18. Let $\operatorname{\mathcal{C}}$ be an $\infty $-category containing a pushout diagram
If $f$ is left orthogonal to a morphism $g: X \rightarrow Y$ of $\operatorname{\mathcal{C}}$, then $f'$ is also left orthogonal to $g$.
Corollary 9.2.7.18. Let $\operatorname{\mathcal{C}}$ be an $\infty $-category containing a pushout diagram
If $f$ is left orthogonal to a morphism $g: X \rightarrow Y$ of $\operatorname{\mathcal{C}}$, then $f'$ is also left orthogonal to $g$.
Proof. We proceed as in the proof of Proposition 9.2.5.15. Let $\pi : \operatorname{\mathcal{C}}_{/Y} \rightarrow \operatorname{\mathcal{C}}$ be the projection map, and let us identify $g$ with an object $\widetilde{X} \in \operatorname{\mathcal{C}}_{/Y}$ satisfying $\pi ( \widetilde{X} ) = X$. By virtue of Corollary 9.2.7.13, it will suffice to show that for any morphism $\widetilde{f}'$ of $\operatorname{\mathcal{C}}_{/Y}$ satisfying $\pi ( \widetilde{f}' ) = f'$, the object $\widetilde{X}$ is weakly $\widetilde{f}'$-local. Since $\pi $ is a right fibration, we can lift (9.18) to a diagram
in the $\infty $-category $\operatorname{\mathcal{C}}_{/Y}$, which is also a pushout square (Proposition 7.1.4.20). By virtue of Remark 9.2.1.10, it will suffice to show that $\widetilde{X}$ is $\widetilde{f}$-local, which follows from our assumption that $f$ is left orthogonal to $g$ (Corollary 9.2.7.13). $\square$